1.

Thevapour pressureof waterat 298 K is 0.0231 barand the vapour pressureof a solutionof 108.24 g of a compound in 1000g of waterat thesame temperatureis 0.0228 bar.Calculate the molar mass of the solute.

Answer»

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Solution :LOWERING in vapour pressure ,
` p_(A)^(@)- p_(A) = 0.0231 - 0.0228`
` = 0.0003` BAR
`(p_(A)^(@) - p_(A))/(p_(A)^(@)) = (w_(B)M_(A))/(w_(A)M_(B))` (For dilutesolutions).
`(0.0003)/(0.0231) = (108.24 xx 18)/(1000 xx M_(B))`
or `"" M_(B) = (108.24 xx 0.0231 xx 18)/(0.0003 xx 1000) = 150.0`


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