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Third period contain 8 elements. Fourth period contain 18 elements. Seven period contain 32 elements. |
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Answer» Solution :For sixth PERIOD , `n = 6` So, `LAMBDA = n - 1, lambda = 6 - 1 = 5 ` Total sub orbitals ` = 1 + 3 + 5 + 7 = 16` Number of electronns = 32 ` :. 32` elements present in 6th period. ENERGY of orbital : `6s lt 4f lt 5d lt 6p`. |
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