1.

Third period contain 8 elements. Fourth period contain 18 elements. Seven period contain 32 elements.

Answer»

Solution :For sixth PERIOD , `n = 6`
So, `LAMBDA = n - 1, lambda = 6 - 1 = 5 `

Total sub orbitals ` = 1 + 3 + 5 + 7 = 16`
Number of electronns = 32
` :. 32` elements present in 6th period.
ENERGY of orbital : `6s lt 4f lt 5d lt 6p`.


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