This question has statement -I and statement - II of the fourchoices given after the statements , choose the one that best describes the two statements . Statement - I : A point particle of mass m movingwith speed v collides with stationary point particle of mass M . If the maximumenergy loss possible is given as f(1/2 mv^(2)) " then" F = (m/(M+m)) Statement-II : Maximumenergy loss occurs when the particles get stuck together as a result of the collision .

This question has statement -I and statement - II of the fourchoices g

1.	This question has statement -I and statement - II of the fourchoices given after the statements , choose the one that best describes the two statements . Statement - I : A point particle of mass m movingwith speed v collides with stationary point particle of mass M . If the maximumenergy loss possible is given as f(1/2 mv^(2)) " then" F = (m/(M+m)) Statement-II : Maximumenergy loss occurs when the particles get stuck together as a result of the collision .
Answer» Statement - I is true , Statement - II is true Statement - II is a correct explanation of Statement -I Statement -I is true , Statement -II is true Statement -II is not a correctexplanation of Statement -I Statement -I is true , Statement -II is false . Statement -I is false , Statement -II is true . Solution :Kinetic energy before collision - Kinetic energy after collision = energy loses `1/2 mv^(2)+1/2 M(o)^(2)-1/2 (m+M)(v)^(2)` = energy loses Where `v = (mv+M XXO)/(m+M)` ` :. V. =m/(m+M) v` `1/2 mv^(2)-1/2 (m+m)(m/(m+m)v)^(2)=` Energy loses ` :. 1/2 mv^(2)-1/2 mv^(2)xx(m/(m+m)v)^(2)` = Energy loses ` :. 1/2 mv^(2)[1-m/(m+m)]^(2)` = Energy loses ` :. 1/2 mv^(2)[1-m/(m+m)]^(2)` = Energy loses `:. f = M/(m+M)` here in statement - I `m/(m+M)` is given . ` :. ` Statement -I is wrong and energy loses BECOMES POSITIVE so maximum energy will be DISSIPATED and hence statement -II is correct .