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This time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4 `ms^(-1)`. The amplitude isA. 1.44 mB. 0.72 mC. 2.88 mD. 0.36 m |
Answer» Correct Answer - A Velocity, `v = r omega cos omega t` `0.4 = r xx (2pi)/(16) xx cos (2 pi)/(16).2 = r xx (2pi)/(16) xx (1)/(sqrt(2))` or `r = (0.4 xx 16 xx sqrt(2))/(2 pi) = (3.2 sqrt(2))/(pi)=1.44 m` |
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