1.

Though the two ends of a glass tube of length 200 cm, hydrogen chlorine gas and ammonia are allowed to enter. At what distance ammonium chloride will first appear ?

Answer»

Solution :By Graham's law of diffusion, `(r_(NH_(3)))/(r_(HCl))=sqrt((M_(HCl))/(M_(NH_(3))))=sqrt((36.5)/(17))=sqrt(2.147)=1.465`.
Thus, `NH_(3)` travels 1.465 times FASTER than HCl. In other words, `NH_(3)` will travel 1.465 cm in the same time which HCl travels 1 cm.
LENGTH of the tube =200 cm.
`:. " Distance TRAVELLED in the tube by "=(1.465)/(1.465+1)xx200=118.9 cm`
Thus, `NH_(Cl)` will first appear at a distance of 118.9 cm from `NH_(3)` end 81.1 cm from HCl end.


Discussion

No Comment Found