1.

Three blocks masses 4kg 6kg and 8kg are connected by a string they are placed on a frictionlesssurface if the system is pulled by a forceof F=36 N then acceleration of the body is a = and tension acting on the sting is T=Which of the following pair is correct

Answer»

`a=4 m//s^(2),T=14 N`
`a=8 m//s^(2),T=7 N`
`a=16 m//s^(2),T=196 N`
`a=4 m//s^(2),T=28 N`

Solution :ACCELERATIONA =` (F )/( m_(1)+ m_(2) + m_(3))`
`= (36)/( 4+ 6+8) = (36)/(18)= 2m//s^(2)`
ByNewtonsecondlaw

`4a = 36 - T_(1)`
`=36 - 4 XX 2`
`=36-8`
`28N`


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