Three blocks of masses 10 kg, 7 kg and 2 kg are placed in contact with each other on a frictionless table. A force of 50 N is applied on the heaviest mass. What is the acceleration of the system?

Three blocks of masses 10 kg, 7 kg and 2 kg are placed in contact with

1.	Three blocks of masses 10 kg, 7 kg and 2 kg are placed in contact with each other on a frictionless table. A force of 50 N is applied on the heaviest mass. What is the acceleration of the system?
Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_PHY_XI_V01_C03_SLV_033_S01.png" width="80%"/> <br/> We know that ` a = [ (<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>)/(m_1 + m_2 + m_3) ] = (<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> N)/(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> kg + <a href="https://interviewquestions.tuteehub.com/tag/7kg-336150" style="font-weight:bold;" target="_blank" title="Click to know more about 7KG">7KG</a> + 2kg) ` <br/>` 50/19 = 2.63 ms^(-2)`</body></html>