Three blocks of masses 10 kg, 7 kg and 2 kg are placed in contact with each other on a frictionless table. A force of 50 N is applied on the heaviest mass. What is the acceleration of the system?

Three blocks of masses 10 kg, 7 kg and 2 kg are placed in contact with

1.	Three blocks of masses 10 kg, 7 kg and 2 kg are placed in contact with each other on a frictionless table. A force of 50 N is applied on the heaviest mass. What is the acceleration of the system?
Answer» Solution : We know that ` a = [ (F)/(m_1 + m_2 + m_3) ] = (50 N)/(10 kg + 7KG + 2kg) ` ` 50/19 = 2.63 ms^(-2)`