InterviewSolution
Saved Bookmarks
| 1. |
Three blocks of masses `m_(1),m_(2)`and `m_(3)` are connected by massless strings as shown on a frictionless table. They are pulled with a force `T_(3)=40N`. If `m_(1)=10kg,m_(2)=6kg` and `m_(3)=4kg` the tension `T_(2)` will be A. 10NB. 20NC. 32ND. 40N |
|
Answer» Correct Answer - C The common acceleration of the blocks is `a (40)/(10+6+4)=(40)/(20)=2 m//s^(2)` `therefore` Tension `T_(2)=(m_(1)+m_(2))a=(10+6)2` `=12xx2=32N`. |
|