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Three blocks of uniform thickness and masses m,m and 2m placed at three corners of a triangle having co-ordinates (2.5,1.5),(3.5,1.5) and (3,3) respectively. Find the centre of mass of the system. |
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Answer» Solution :Centre of mass of the SYSTEM is GIVEN by `x_(CM)=(m(2.5)+m(3.5)+2m(3))/(m+m+2m)` `=2` `y_(CM)=(m(1.5)+m(1.5)+2m(3))/(m+m+2m)` `=2.25` |
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