1.

Three bodies are lying on a frictionless horizontal table and these are connected as shown in the figure. They are pulled towards right with a force T_(3) = 60N If m_(1), m_(2)and m_(3), are equal to 10 kg, 20kg and 30kg respectively, then the values of T_(1) and T_(2) will be

Answer»

`10N,10N`
`30N,10N`
`10N,30N`
`10N,10N`

SOLUTION :`T_(3)-T_(2)=m_(3)a,`
`T_(2)-T_(1)=m_(2)a, T_(1)=m_(1)a, a=(T_(3))/(m_(1)+m_(2)+m_(3))`


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