Saved Bookmarks
| 1. |
Three capillary tubes of some radius 1 cm but of lengths 1m, 2m and 3m are fitted horizontally to the bottom of a long vessel containing a liquid at constant pressure land flowing through these tubes. What is the length of a single tube which can replace the three capillaries. |
|
Answer» Solution :`V_(1)=(piPr^(4))/(8 eta1_(1)),V_(2)=(piPr^(4))/(8 eta 1_(2)),V_(3)=(piPr^(4))/(8 eta I_(3))` and `V=(piPr^(4))/(8etal)` Now `V=V_(1)+V_(2)+V_(3)implies1/l+1/(l_(1))+1/(l_(2))+1/(l_(3))` Susbtituting the VALUES we get `l=(l_(1)l_(2)_(3))/(l_(1)l_(2)+l_(1)l_(3)+l_(2)l_(3))=(1xx2xx3)/(1xx2+1xx3+2xx3)=6/11` m |
|