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Three circles are described with a radius of 10 cm at the corner of the equilateral triangle as the center. So that each touches the other two. Find the uncommon area of the triangle and the circle. (Take √3 = 1.73)1. 15.86 cm22. 10.86 cm23. 20.86 cm24. 21 cm2 |
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Answer» Correct Answer - Option 1 : 15.86 cm2 Given: The radius of the circle = 10 cm Formula used: Area of an equilateral triangle = (√3/4) × side2 Area of sector = (θ/360) × πr2 Where, r = radius of the circle Calculation: Area of the equilateral triangle ⇒ (√3/4) × 20 × 20 ⇒ 100 × 1.73 ⇒ 173 Area of the 3 sector ⇒ 3 × (60/360) × (22/7) × 10 × 10 ⇒ 157.14 Area of the uncommon area ⇒ 173 – 157.14 ⇒ 15.86 ∴ The area of the uncommon area is 15.86 cm2. |
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