Three coins are tossed, find the probability of getting 1. Exactly on

1.	Three coins are tossed, find the probability of getting 1. Exactly one Head 2. Exactly 2H 3. No ehads/only tails
Answer» S = {HHH, HHT, HTT, TTT, TTH, THH, THT, HTH} : n = 23 = 8 1. m = Getting exactly one Head : (HTT, TTH, THT) = 3 . P(One H) = m/n = 3/8 2. m = Exactly 2 H : (HHT, THH, HTH) = 3 P(2H) = 3/8 3. m = no heads/ Tails only : (TTT) =1 P(No heads/Tails only) = m/n = 1/8.

Three coins are tossed, find the probability of getting 1. Exactly one Head 2. Exactly 2H 3. No ehads/only tails

Answer»

S = {HHH, HHT, HTT, TTT, TTH, THH, THT, HTH} : n = 23 = 8

1. m = Getting exactly one Head : (HTT, TTH, THT) = 3 .

P(One H) = m/n = 3/8

2. m = Exactly 2 H : (HHT, THH, HTH) = 3

P(2H) = 3/8

3. m = no heads/ Tails only : (TTT) =1

P(No heads/Tails only) = m/n = 1/8.