1.

Three compounds I, II, and III are given. (I) (II)(III) The compounds (A), (B) and (C ), respectively, are:

Answer»

I, II, and III
I, III, and II
II, I, and III
II, III, and I.

Solution :`B_(2)H_(6)//THF` also reduces `(C==O)` group to `(-CHOH)` group and `(-COOH)` group to `(CH_(2)OH)`, alolng with reacting at `(C=C)` bond to FORM alcohol (anti-Markovnikov's rule).


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