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Three consecutive integers add up to 51. What are these integers? |
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Answer» Let three consecutive integers be x, x + 1, and x + 2. Sum of these numbers = x+ x + 1 + x + 2 = 51 3x + 3 = 51 On transposing 3 to R.H.S, we obtain 3x = 51 − 3 3x = 48 On dividing both sides by 3, we obtain 3x/3 = 48/3 x = 16 x + 1 = 17 x + 2 = 18 Hence, the consecutive integers are 16, 17, and 18. |
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