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Three consecutive positive integers are such that the sum of the squareof the first and the product of other two is 46, fond the integers. |
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Answer» Correct Answer - 4,5,6 Let the required numbers be `x,(x+1)" and "(x+2).` Then, `x^(2)+(x+1)(x+2)=46implies2x^(2)+3x-44=0implies2x^(2)+11x-8x-44=0` `implies(2x+11)(x-4).` `xne(-11)/(2)`, since x is an integer. |
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