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Three cubes of metal with edges 3cm, 4 cm and 5 cm respectively are melted to form a single cube. The lateral surface area of the new cube formed isA. `72 cm^(2)`B. `144 cm^(2)`C. `128 cm^(2)`D. `256 cm^(2)` |
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Answer» Correct Answer - B Volume of new cube formed `= (3^(3) + 4^(3) + 5^(3)) cm^(3)` `= (27 + 64 + 125) cm^(3) = 216 cm^(3)` Let `a^(3) = 216 = 6^(3)`. Then, a = 6 cm Lateral surface area of the new cube `= 4a^(2) = (4 xx 6 xx 6) cm^(2) = 144 cm^(2)` |
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