Three cubes whose edges measure 3 cm, 4 cm, and 5 cm respectively are

1.	Three cubes whose edges measure 3 cm, 4 cm, and 5 cm respectively are melted to form a new cube. Find the surface area of the new cube formed.
Answer» Given details are, Edge of three cubes are = 3cm, 4cm, 5cm Sum of volume of these cubes = 3³ + 4³ + 5³ = 27 + 64 + 125 = 216 cm³ After these cubes are melted, a new cube is formed. Let edge length of this new cube be ‘a’ cm a³ = 216 a = √216 = 6cm Edge of new cube is = 6cm ∴ Surface area of new cube = 6 × a² = 6 × 6² = 6 × 36 = 216cm²

Three cubes whose edges measure 3 cm, 4 cm, and 5 cm respectively are melted to form a new cube. Find the surface area of the new cube formed.

Answer»

Given details are,

Edge of three cubes are = 3cm, 4cm, 5cm

Sum of volume of these cubes = 3³ + 4³ + 5³

= 27 + 64 + 125

= 216 cm³

After these cubes are melted, a new cube is formed.

Let edge length of this new cube be ‘a’ cm

a³ = 216

a = √216

= 6cm

Edge of new cube is = 6cm

∴ Surface area of new cube = 6 × a²

= 6 × 6²

= 6 × 36

= 216cm²