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Three different numbers are selected at random from the set `A = (1, 2, 3,...., 10).` The probability that the product of two of the numbers is equal to the third isA. `(3)/(4)`B. `(1)/(40)`C. `(1)/(8)`D. `(39)/(40)` |
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Answer» Correct Answer - B Out of 10 numbers, three numbers can be chosen in `.^(10)C_(3)` ways. `therefore` Total number of elementary events `=.^(10)C_(3)` The product of two numbers, out of the chosen numbers, will be equal to the third number if the numbers are chosen in one of the following ways : (2,3, 6), (2, 4, 8), (2, 5, 10) `therefore` Favourable number of elementary events =3 Hence, required probability `=(3)/(.^(10)C_(3))=(1)/(40)` |
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