1.

Three elastic wires PQ, PR and PS support a body P of mass M, as shown in figure. The wires are of the some material and cross sectional area, the middle one being vertical. Find the loads by each wire.

Answer»

`Mg//1+ 2 cos^(2)THETA`
`Mg//1+ 2 cos^(3)theta`
`Mg cos^(2)theta//1+ 2cos^(3)theta`
`Mg costheta//1+ 2cos^(3)theta`

Solution :Figure shows the situationwhentheload (boby P) descends dueto thestretchinload wires. The new positionsof wires PQ andPsare shown by thedotted lines. Let `T_(1), T_(2)` and`T_(3)`be the loads(tensions) carried by the three wires PQ, PR and PS respectivelywith thewires PQ and PS makingangle `theta` with the vertical .

Consideringthe horizontal equilibrium ofpointP,
`T_(1)sin theta= T_(3) sin rArr T_(1) = T_(3) = T("SAY")`
Considering the veritcalequilibrium of point P, `T_(2) +2T cos theta = Mg""......(i)`
PR =a
`THEREFORE ` PQ = PS = a sec`theta`
I f`deltal_(1)` and `deltal_(2)` bethe elongations in thewires PR and PQ (or Ps ) respectively then
`deltal_(2) = deltal_(1) cos theta` (from geometry)
If A nd Y be the cross- sectional area and Young'smodaulus of reachof the each of the three wires, then
`(T)/(AY)(a sectheta) = (T_(2))/(AY ) a cos theta rArr T =T_(2) cos ^(2) theta""....(ii)`
Sloving eqns. (i) and (ii) we get `T_(2) = (Mg)/(1+2 cos^(3) theta)`


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