InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Three faradays of electricity are passed through molten `Al_2O_3` aqueous solution of `CuSO_4` and molten `NaCl` taken in deffernt electrolytic cells. The amout of `Al,Cu` and Na deposited at the cathodes will be in the ration of .A. 1 mole :2 mole: 3 moleB. 3 mole : 2 mole : 1 moleC. 1 mole : 1.5 mole : 3 moleD. 1.5 mole : 2 mole : 3 mole |
|
Answer» Correct Answer - C At cathode: `Al^(3+)+3e^(-)toCu` `E_(Cu)=("Atomic mass")/(3)` At cathode: `Cu^(2+)+2e^(-)toCu` `E_(Cu)=("Atomic mass")/(2)` At cathode: `Na^(+)+e^(-)toNa` `E_(Na)=("Atomic mass")/(1)` For the passage of 3 faraday, mole atoms of Al deposited=1 mole atoms of Cu deposited`=(1xx3)/(2)=1.5` mole atoms of Na deposited `=1xx3=3`. |
|