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Three forces `(vec(F)_(1), vec(F)_(2), vec(F)_(3))` are acting an a particle moving vertically up with constant speed. Two force `vec(F)_(1)=-10hat(j)N`, and `vec(F)_(1)=-6hat(i)=8hat(j)` , N are acting an particle on acting on particle respectively find `vec(F)_(3)`.

Answer» `Sigma_(vec(F))=vec(0) i.e`
`vec(F_(1))+vec(F_(2))+vec(F_(3))=vec(0)`
`vec(F_(3))=-(vec(F_(1))+vec(F_(2)))`
`=-(-6hat(i)-2hat(j))`
`vec(f_(3))=6hat(i)+2hat(j) N`


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