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Three gases A, B and C were taken at partial pressures of 1 bar each along with excess of liquide D so thet following equation was established. A(g)+B(g)hArrC(g)+D(g) Calculate partial pressure of C (in pascal ) when equalibrium gets established in the container at 300 k. Given:DeltaG^(@)f A (g) =- 200 kcal/mole DeltaG^(@)f D(l)=-49.58 kcal/mole DeltaG^(@)f B (g0 =-100 Kcal/mole DeltaG^(@)f D (g)=-49.58 kcal/mole DeltaG^(@)f C (g) =- 250 kcal/mole R=2 cal/mol K, In 2=0.7 sqrt5= 2.24 all data are given at 300 K. Divede your answer by 10 and fill the OMR. |
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