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Three identical particles with velocities `v_0hati`, `-3v_0hatj` and `5v_0hatk` collide successively with each other in such a way that they form a single particle. The velocity vector of resultant particle isA. (a) `v_0/3(hati+hatj+hatk)`B. (b) `v_0/3(hati-hatj+hatk)`C. (c) `v_0/3(hati-3hatj+hatk)`D. (d) `v_0/3(hati-3hatj+5hatk)` |
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Answer» Correct Answer - D `p_1=p_f` `:.m(v_0hati)+m(-3v_0hatj)+m(5v_0hatk)` `=3mv` `:. v=(v_0)/(3)(hati-3hatj+5hatk)` |
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