InterviewSolution
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InterviewSolution
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Three immiscible liquids of densities `d_1 gt d_2 gt d_3` and refractive indices `mu_1 gt mu_2 gt mu_3` are put in a beaker. The height of each liquid column is `(h)/(3)`. A dot is made at the bottom of the beaker. For near normal vision, find the apparent depth of the dot.A. `h/6(1/(mu_(1))+1/(mu_(2))+1/(mu_(3)))`B. `h/6(1/(mu_(1))-1/(mu_(2))-1/(mu_(3)))`C. `h/3(1/(mu_(1))-1/(mu_(2))-1/(mu_(3)))`D. `h/3(1/(mu_(1))+1/(mu_(2))+1/(mu_(3)))` |
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Answer» Correct Answer - D Apparent depth of the dot `= (h)/(3mu_(1)) + (h)/(3mu_(2)) + (h)/(3mu_(3)) = (h)/(3)[(1)/(mu_(1))+(1)/(mu_(2)) + (1)/(mu_(3))]` |
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