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Three indentical uniform blocks of mass m each and length L are placed on a smooth fixed horizontal surface as shown. There is friction between A and B (Friction cofficient `mu`) while there is no friction between A and C. At the instant shown, that is at t=0, the block A has horizontal velocity of magnitude u towards right, whereas speed of B and C is zero. At the instant block A has covered a distance L relative to block B velcity of all blocks are same. The value of `mu` isA. `mu =3/2 (u^(2))/(gL)`B. `mu=1/2 (u^(2))/(gL)`C. `mu=(u^(2))/(gL)`D. `mu =2/3(u^(2))/(gL)` |
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Answer» From conservation of momentum `3mv="mu"` or `v=(u)/(3)` Net workdone by friction `=(1)/(2)3m((u)/(3))^(2)-(1)/(2)"mu"^(2)=-(1)/(3)"mu"^(2)` net work done by fricktion `=underset(r)overset(0)intmu(xlambdag)(-dx)=-mulambdag(L^(2))/(2)` Also magnitude of net work done by friction `=mulambdag(L^(2))/(2)=mumg(L)/(2)` `therefore(1)/(3)"mu"^(2)=mumg(L)/(2)` or `mu=(2)/(3)(u^(2))/(gL)` `3mg="mu"` or `v=(u)/(3)` |
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