Three long straight conductors are kept perpendicular to the plane of paper. Currents `2A,3A` are passing through the two conductors into the plane of paper in first two conductors and `5A` current passes through thirst conductor, directed out of the paper. A closed loop encloses the conductors, then the value of `oint bar(B). bar(dl)` over the closed loop is `(` assume current into the paper as negative and out of the paper as positive `)`A. `2 mu_(0)`B. zeroC. `- mu_(0)`D. `+ mu_(0)`

Three long straight conductors are kept perpendicular to the plane of

1.	Three long straight conductors are kept perpendicular to the plane of paper. Currents `2A,3A` are passing through the two conductors into the plane of paper in first two conductors and `5A` current passes through thirst conductor, directed out of the paper. A closed loop encloses the conductors, then the value of `oint bar(B). bar(dl)` over the closed loop is `(` assume current into the paper as negative and out of the paper as positive `)`A. `2 mu_(0)`B. zeroC. `- mu_(0)`D. `+ mu_(0)`
Answer» Correct Answer - 2 `ointB.dl=mu_(0)i`

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