Three men can complete a piece of work in 6 days. Two days after they

1.	Three men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will they take to complete the remaining work?1. 42. 13. 34. 2
Answer» Correct Answer - Option 4 : 2 Given: Three men can complete a piece of work in 6 days. Formula used: \(\frac{M_{1}\ × \ D_{1}}{W_{1}}\ =\ \frac{M_{2}\ × \ D_{2}}{W_{2}}\) where M₁= M₂ = number of man D1 = D2 = number of days W1 = W2 = part of work Calculations: time taken = 6 days part of work done in 1 day = 1/6 part work done in 2 days = (1/6) × 2 = 1/3 remaining work = 1 - 1/3 = 2/3 so using above formula we get \(\frac{3\ \times\ 2}{\frac{1}{3}}\ =\ \frac{6\ \times\ D_{2}}{\frac{2}{3}}\) so D₂ = 2 days. ∴ the correct answer is 2 days.

Three men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will they take to complete the remaining work?1. 42. 13. 34. 2

Answer» Correct Answer - Option 4 : 2

Given:

Three men can complete a piece of work in 6 days.

Formula used:

\(\frac{M_{1}\ × \ D_{1}}{W_{1}}\ =\ \frac{M_{2}\ × \ D_{2}}{W_{2}}\)

where M₁= M₂ = number of man

D1 = D2 = number of days

W1 = W2 = part of work

Calculations:

time taken = 6 days

part of work done in 1 day = 1/6

part work done in 2 days = (1/6) × 2 = 1/3

remaining work = 1 - 1/3 = 2/3

so using above formula we get

\(\frac{3\ \times\ 2}{\frac{1}{3}}\ =\ \frac{6\ \times\ D_{2}}{\frac{2}{3}}\)

so D₂ = 2 days.

∴ the correct answer is 2 days.

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