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Three moles of an ideal gas are expanded isothermally from a volume of 300 cm3 to 2.5 dm3 at 300 K against a pressure of 1.9 bar. Calculate the work done in L atm and joules. |
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Answer» Given : Number of moles of a gas = n = 3 mol Initial volume = V1 = 300 cm3 = 0.3 dm3 Final volume = V2 = 2.5 dm3 External pressure = Pex = 1.9 bar Temperature = T = 300 K ∵ W = -Pex (V2 – V1) = -1.9 (2.5 – 0.3) = - 4.18 dm3bar Now, 1 dm3bar = 100 J ∴ W = -4.18 × 100 = -4180 J ∴ Work of expansion = W = -4180 J |
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