1.

Three moles of an ideal gas are expanded isothermally from a volume of 300 cm3 to 2.5 dm3 at 300 K against a pressure of 1.9 bar. Calculate the work done in L atm and joules.

Answer»

Given : 

Number of moles of a gas = n = 3 mol

Initial volume = V1 = 300 cm3

= 0.3 dm3

Final volume = V2 = 2.5 dm3

External pressure = Pex = 1.9 bar

Temperature = T = 300 K

∵ W = -Pex (V2 – V1)

= -1.9 (2.5 – 0.3)

= - 4.18 dm3bar

Now, 

1 dm3bar = 100 J

∴ W = -4.18 × 100

= -4180 J

∴ Work of expansion = W = -4180 J



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