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Three moles of helium gas at one atmosphere are compressed reversibly and isothermally at 127^(@)C to 5 atmospheres. Calculate the work done. |
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Answer» <P> Solution :`T = 127^(@)C = 127 + 273 = 400 K, P_(1) = 1` atm, `P_(2) = 5` atm`R = 8.314 J//K mol, n = 3 "mole"` `w = -2.303 nRT LOG ((P_(1))/(P_(2))) = -2.303 xx 3 xx 8.314 xx 400 xx log ((1)/(5))` `= -2.303 xx 3 xx 8.134 xx 400 xx BAR(1).3010` `= -2.303 xx 3 xx 8.314 xx 400 xx (-0.6990) = +16,060 "joule" = +16.06 kJ` |
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