1.

Three moles of PCl_(5). three moles of PCl_(3) and two moles of Cl_(2) are taken in a closed vessel. IF at equlibrium the vessel has 1.5 moles of PCl_(5), the number of moles of PCl_(3) present in it is

Answer»

6
`4.5`
5
3

Solution :`PCl_(5(G))hArrPCl_(3(g))+Cl_(2(g))`
`{:("3",3,2,("Initially")),("(3-x)",(3+x),(2+x),("Aqulibrium")):}`
Given that, `(3-x)=1.5, thereforex=1.5,` THEREFORE no. of moles of `PCl_((g))Presentis =3+1.5=4.5`


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