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Three particles A, B and C are thrown from the top of a tower with the same speed. A is thrown up, B is thrown down and C is horizontally. They hit the ground with speeds `v_(A),v_(B) and v_(C)` respectively then,A. `v_(A)=v_(B)=v_(C)`B. `v_(A) gt v_(B) gt v_(C)`C. `v_(A)=v_(B) gt v_(C)`D. `v_(A) gt v_(B)=v_(C)` |
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Answer» Correct Answer - A |
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