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Three particles A, B and C are thrown from the top of a tower with the same speed. A is thrown straight up, B is thrown straight down and C is thrown horizontally. They hit the ground with speeds vA, vB and vC respectively.(a) vA = vB = vC(b) vB > vC > vA (c) vA = vB > vC (d) vA > vB = vC |
Answer» Correct answer is: (a) vA = vB = vC The increase in kinetic energy = the loss in potential energy. This is the same for all three. |
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