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Three particles each of mass 100g are placed at the vertices of an equilateral triangle of side length 10cm. Find the moment of inertia of the system about an axis passing through the centroid of the triangle and perpendicular to its plane. |
Answer» <html><body><p></p>Solution :`m=100g=100xx10^(-3)<a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>`, side `a=10cm=0.1m` <br/> Moment of <a href="https://interviewquestions.tuteehub.com/tag/inertia-1043176" style="font-weight:bold;" target="_blank" title="Click to know more about INERTIA">INERTIA</a> `I=3m^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/> `=3xx100xx10^(-3)((10)/(sqrt(3)xx10^(-2))^(2)=10^(-3)kkgm^(2)`</body></html> | |