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Three particles, each of the mass `m` are situated at the vertices of an equilateral triangle of side `a`. The only forces acting on the particles are their mutual gravitational forces. It is desired that each particle moves in a circle while maintaining the original mutual separation `a`. Find the initial velocity that should be given to each particle and also the time period of the circular motion. `(F=(Gm_(1)m_(2))/(r^(2)))` |
Answer» Correct Answer - A `F_(A) = F _(AB) +F_(AC)` `= 2[(Gm^(2))/(a^(2))]cos30^(@) = sqrt 3[(Gm^(2))/(a^(2))]` `r = (a)/(sqrt3)`, `(m upsilon^(2))/(r) = F` or `(sqrt3m upsilon ^(2))/(a) = (sqrt3Gm^(2))/(a)` `upsilon = sqrt ((Gm)/(a))`. |
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