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Three particles of masses `20g`, `30g` and `40g` are initially moving along the positive direction of the three coordinate axes respectively with the same velocity of `20cm//s`. When due to their mutual interaction, the first particle comes to rest, the second acquires a velocity `(10hati+20hatk)cm//s`. What is then the velocity of the third particle?A. `2hati+3hatj+4hatk`B. `2.5hati+15hatj+5hatk`C. `2.5hati+10hatj-5hatk`D. `2hati-3hatj-4hatk` |
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Answer» Correct Answer - B `P_(1)=20xx20hati, P_(3)=40xx20hatk` `P_(2)=30xx20 hatj` `P_(1)=P_(1)+P_(2)+P_(3)=P_(f)` `rArr 400i+600hatj+800hatk=30(10i+20 hatk)+40 v` get `V=(100i+600hatj+200hatk)/40` `=2.5 hati+15 hatj +5 hatk` |
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