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Three pieces of timber 42 m, 49 m and 63 m long have to be divided into planks of the same length. What is the greatest possible length of each plank? How many planks are formed? |
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Answer» Given: The lengths of three pieces of timber are 42 m, 49 m and 63 m respectively. We have to divide the timber into equal length of planks. Greatest possible length of each plank = HCF (42, 49, 63) The prime factorization of 42, 49 and 63 are: 42 = 2 x 3 x 7 49 = 7 x 7 63 = 3 x 3 x 7 HCF (42, 49, 63 ) = 7 The greatest possible length of each plank is 7 m. Again, The number of planks can be formed = 22 |
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