Three Pipes A, B And C Can Fill A Tank In 6 Hours. After Working At I

1.	Three Pipes A, B And C Can Fill A Tank In 6 Hours. After Working At It Together For 2 Hours, C Is Closed And A And B Can Fill The Remaining Part In 7 Hours. The Number Of Hours Taken By C Alone To Fill The Tank Is?
Answer» Tank part filled by pipes (A+B+C) in 1 hrs = 1/6 ------- (1) so tank part filled by (A+B+C) in 2 hrs = 21/6 = 1/3 Now find the REMAINING part = (1-1/3) = 2/3 => (A+B) 7 hs WORK = 2/3 so (A+B) 1 hrs work = 2/21 ------ (2) To find the C 1 hrs work use eq. 1 & 2 => 1/6-2/21 = 1/14 so C alone can FILL the tank in 14 hrs. Tank part filled by pipes (A+B+C) in 1 hrs = 1/6 ------- (1) so tank part filled by (A+B+C) in 2 hrs = 21/6 = 1/3 Now find the remaining part = (1-1/3) = 2/3 => (A+B) 7 hs work = 2/3 so (A+B) 1 hrs work = 2/21 ------ (2) To find the C 1 hrs work use eq. 1 & 2 => 1/6-2/21 = 1/14 so C alone can fill the tank in 14 hrs.

Three Pipes A, B And C Can Fill A Tank In 6 Hours. After Working At It Together For 2 Hours, C Is Closed And A And B Can Fill The Remaining Part In 7 Hours. The Number Of Hours Taken By C Alone To Fill The Tank Is?

Answer»

Tank part filled by pipes (A+B+C) in 1 hrs = 1/6 ------- (1)

so tank part filled by (A+B+C) in 2 hrs = 2*1/6 = 1/3

Now find the REMAINING part = (1-1/3) = 2/3

=> (A+B) 7 hs WORK = 2/3

so (A+B) 1 hrs work = 2/21 ------ (2)

To find the C 1 hrs work use eq. 1 & 2

=> 1/6-2/21 = 1/14

so C alone can FILL the tank in 14 hrs.

Tank part filled by pipes (A+B+C) in 1 hrs = 1/6 ------- (1)

so tank part filled by (A+B+C) in 2 hrs = 2*1/6 = 1/3

Now find the remaining part = (1-1/3) = 2/3

=> (A+B) 7 hs work = 2/3

so (A+B) 1 hrs work = 2/21 ------ (2)

To find the C 1 hrs work use eq. 1 & 2

=> 1/6-2/21 = 1/14

so C alone can fill the tank in 14 hrs.