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Three point A, B and C with position vectors a_(1)=3hati-2hatj-hatk, a_(2)=hati+3hatj+4hatk and a_(3)=2hati+hatj-2hatk relative to an origin O. The distance of A from the plane OBC is (magnitude) |
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Answer» 5 i.e., `a_(1)*(a_(2)xxa_(3))=0` The distanceof A from the plane `OBC = |(a_(1)*(a_(2)xxa_(3)))/(|a_(2)xxa_(3)|)|` `a_(2)xxa_(3) = -10hati + 10 hatj - 5hatk` `rArr| a_(2) xx a_(3)|=15` `THEREFORE ` DISTANCE ` = (1)/(15)||(3,-2,-1),(1,3,4),(2,1,-2)||=3` |
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