1.

Three point masses m_(1) , m_(2), m_(3) are located at the vertices of an equilateral triangle of length a. The moment of inertia of systein about an axis along the altitude of the triangle passing through m_(1) is

Answer»

`(m_(2) + m_(3)) (a^2)/(4)`
`(m_(1) + m_(2) + m_(3))a^(2)`
`(m_(1) + m_(2)) (a^2)/(2)`
`(m_(2) + m_(3)) a^(2)`

Solution :Perpendicular distance of `m_(2)` and `m_(3)` from altitude of TRIANGLE = `a cos 60^(@) = (a)/(2)`
The moment of inertia of the system about the given axis is `I = m_1 XX 0^2 + m_(2) ((a)/(2))^(2) + m_(3) ((a)/(2))^(2) = (m_(2) + m_(3)) (a^(2))/(4)`


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