Three resistance of 4ohms, 6ohms and 10ohms are connected in series. T

1.	Three resistance of 4ohms, 6ohms and 10ohms are connected in series. The potential difference across the combination is 5V. Calculate the potential difference across each resister. Plz solve
Answer» ANSWER: total resistance=4+6+10=20 potential diff=5v current I=v/r =5/20 =1/4 ampere now for 1st resistance i=1/4 r=4ohm so v=ir =1/4×4 =1 v for 2ND, r=6,i=1/4 v=ir =1/4×6=1.5v for 3RD, r=10.i=1/4 v =ir =10/4 =2.5v smjh to gye hi HOGE.

Three resistance of 4ohms, 6ohms and 10ohms are connected in series. The potential difference across the combination is 5V. Calculate the potential difference across each resister. Plz solve

Answer»

total resistance=4+6+10=20

potential diff=5v

current I=v/r

=5/20

=1/4 ampere

now for 1st resistance

i=1/4

r=4ohm

so v=ir

=1/4×4

=1 v

for 2ND,

r=6,i=1/4 v=ir

=1/4×6=1.5v

for 3RD,

r=10.i=1/4 v =ir

=10/4

=2.5v

smjh to gye hi HOGE.