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Three resistors of `6 Omega,2 Omega` and `x` are connected in series to a cell of emf `1.5 V`. The current registered is `(1//6) A`. Calculate the value of `x`. |
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Answer» Correct Answer - `1 Omega` As `I = (V)/( R), (1)/(6) = (1.5)/(6 + 2 + x)` or `8 + x = 9` or `x = 1 Omega`. |
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