Three rods of equal length of same material are joined to form an equivalent triangle `ABC` as shown figure. Area of cross-section of rod `AB` is `S` of rod `BC` is `2S` and that of `AC` is `S` , then `{:(,"Column-I",,"Column-II"),((A),"Temperature of junction" B,(p),"Greater than" 50^(@)C),((B),"Heat current in" AB,(q),"Less than" 50^(@)C),((C),"Heat current in BC",(r),"Is equal to current in BC"),(,,(s),"Is " 2/3 "times heat current in AC"),(,,(t),"None"):}`

Three rods of equal length of same material are joined to form an equi

1.	Three rods of equal length of same material are joined to form an equivalent triangle `ABC` as shown figure. Area of cross-section of rod `AB` is `S` of rod `BC` is `2S` and that of `AC` is `S` , then `{:(,"Column-I",,"Column-II"),((A),"Temperature of junction" B,(p),"Greater than" 50^(@)C),((B),"Heat current in" AB,(q),"Less than" 50^(@)C),((C),"Heat current in BC",(r),"Is equal to current in BC"),(,,(s),"Is " 2/3 "times heat current in AC"),(,,(t),"None"):}`
Answer» Let `R_(BC) = R` then `R_(AB) = R_(AC) = 2R` as `R = (l)/(kA)` `(100-T_(B))/(2R) = (T_(B)-0)/(R) implies T_(B) = 67.7 ^(@)C` `((DeltaQ)/(Deltat))_(AB) = ((DeltaQ)/(Deltat))_(BC)` and `((DeltaQ)/(Deltat))_(AB)= (2)/(3)((DeltaQ)/(Deltat))_(AC)`

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