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    				| 1. | Three rods of uniform area of cross section `A =10^(-7)m^(2)` are arranged as shown in Fig Find out the shift in point `B, C` and `D`. | 
| Answer» `/_L_(B)=/_L_(AB)=(FL)/(AL)=(MgL)/(AY)` `=(10x10x0.1)/(10^(-7)xx2.5xx10^(10))=4xx10^(-3)m=4mm` `/_L_(C)=/_L_(B)+/_L_(BC)` `=4xx10^(-3)+(10xx0.2)/(10^(-7)xx4xx10^(10))` `/_L_(C)=/_L_(B)+/_L_(BC)` `=4xx10^(-3)+(100xx0.2).(10^(-7)x10^(-3)+5xx10^(-3))=9mm` `=4xx10^(-3)+5xx10^(-3)=24mm` `/_L_(D)=/_L_(C)+/_L_(CD)` `=9xx10^(-3)+(100xx0.15)/(10^(-7)xx1xx10^(10))` `=9xx10^(-3)+15xx10^(-3)=24mm` | |