Three solid cubes of sides 1 cm, 6 cm and 8 cm are melted to form a ne

1.	Three solid cubes of sides 1 cm, 6 cm and 8 cm are melted to form a new cube. Find the sin-face area of the cube so formed.
Answer» Volume of new cube = (13 + 63 + 83) cm³ = (1 + 216 + 512) cm³ = 729 cm³ Edge of new cube = \(\sqrt [ 3 ]{ 729cm^{ 3\qquad } }\) = 9 cm Surface area of the cube so formed = 6 x (edge)² = 6 x (9)² = 6 x 81 = 486 cm²

Three solid cubes of sides 1 cm, 6 cm and 8 cm are melted to form a new cube. Find the sin-face area of the cube so formed.

Answer»

Volume of new cube

= (13 + 63 + 83) cm³

= (1 + 216 + 512) cm³

= 729 cm³

Edge of new cube

= \(\sqrt [ 3 ]{ 729cm^{ 3\qquad } }\)

= 9 cm

Surface area of the cube so formed

= 6 x (edge)² = 6 x (9)²

= 6 x 81 = 486 cm²