Three solutions eaach of 100 mL containing 0.4 M As_(2)S_(3),5M NaOH and 6MH_(2)O_(2), respectively were mixed to form AsO_(4)^(3-) and SO_(4)^(2-) as products. Q. When the above solution is allowed to stand for some time what volume of O_(2) will be obtained STP?

Three solutions eaach of 100 mL containing 0.4 M As_(2)S_(3),5M NaOH a

1.	Three solutions eaach of 100 mL containing 0.4 M As_(2)S_(3),5M NaOH and 6MH_(2)O_(2), respectively were mixed to form AsO_(4)^(3-) and SO_(4)^(2-) as products. Q. When the above solution is allowed to stand for some time what volume of O_(2) will be obtained STP?
Answer» 0.112 L 0.224 L 0.224L 0.448L SOLUTION :If a `H_(2)O_(2)` solution is allowed to stand, it decomposes to `O_(2)` and `H_(2)O` `underset(40)(H_(2)O_(2)tounderset(0)(H_(2)O)+(1)/(2)underset(0)(O_(2))` `{:(mmol es),(of H_(2)O_(2)),(l eft)]:}-(1)/(2)xx40=20m" mol of "O_(2)` THUS, mmol es of O_(2)formed`=40xx(1)/(2)=20` Volume of `O_(2)` at `STP=20xx10^(-3)xx22.4L` `(because1 " mol of "O_(2) at STP=22.4L)` `=0.448L`