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Three suggestion are made for ways to removes silver ions from solution: a. Make the solution `0.01M`in `Nal`. b. Buffer the solution at `pH = 13`. c. Make the solution `0.01M Na_(2)S`. What will be the equilibrium silver ion concentartion in each case? which course of action is most effective in removing `Ag^(o+)` ions? `K_(sp) (AgI) = 8.5 xx 10^(-17), K_(sp) (AgOH) = 2 xx 10^(-8)`, `K_(sp) (Ag_(2)S) = 5.5 xx 10^(-51)` |
Answer» `Ag1 hArr Ag^(o+) + I^(Θ)`, `AgOH hArr Ag^(o+) + overset(Θ)OH` `Ag_(2)S hArr 2Ag^(o+) + S^(2-)` a. `[Ag^(o+)] = (8.5 xx 10^(-17))/(10^(-2)) = 8.5 xx 10^(-15) M` b. `pH = 13 :. [H^(o+)] = 10^(-13), [overset(Θ)OH] = 10^(-1)` `[Ag^(o+)] = (2xx10^(-8))/(10^(-1)) = 2xx 10^(-7)M` c. `[Ag^(o+)] = sqrt((5.5 xx 10^(-51))/(10^(-3))) = 2.345 xx 10^(-24) M` |
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