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Three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest oneFind the numbers. |
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Answer» Numbers are as x,x+2,x+4 largest=x+4 smallest=x so, 3x-7=2(x+4)3x-7=2x+83x-2x=8+7x=15 therefore,first no.=x=15second no.=x+2=15+2=17third no.=x+4=15+4=19 15,17,19 ans |
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