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Three uniform circular disc, each of mass 0.5 kg and radius 10 cm, are kept in contact with each other as shown in the figure. Find the moment of inertia of the system when it rotates about the axis AB. |
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Answer» Solution :`I=I_(1)+I_(2)+I_(3)` `I=(5MR^(2))/(4)+(5MR^(2))/(4)+(MR^(2))/(4)rArr I=(11 MR^(2))/(4)` `M=0.5 kg, r =10 CM = 10xx10^(-2)m` `THEREFORE` Moment of INERTIA of the SYSTEM `I=(11MR^(2))/(4)=(11xx0.5xx(0.1)^(2))/(4)` `=1.375xx10^(-2)kg m^(2)`.
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