Three Years Ago The Average Age Of A And B Was 18 Years With C Joinin

1.	Three Years Ago The Average Age Of A And B Was 18 Years With C Joining Them, Then The Average Becomes 22 Years. How Old Is C Now?
Answer» Sum of ages of A and B, 3 Years ago =(18 x 2) = 36 Years Sum of ages of A, B and C, Now = (22 x 3) = 66 Years Sum of ages of A and B, Now = (36 +6)Years = 42 Years THEREFORE, C’s age = (66 - 42)Years = 24 Years. Sum of ages of A and B, 3 Years ago =(18 x 2) = 36 Years Sum of ages of A, B and C, Now = (22 x 3) = 66 Years Sum of ages of A and B, Now = (36 +6)Years = 42 Years Therefore, C’s age = (66 - 42)Years = 24 Years.

Three Years Ago The Average Age Of A And B Was 18 Years With C Joining Them, Then The Average Becomes 22 Years. How Old Is C Now?

Answer»

Sum of ages of A and B, 3 Years ago =(18 x 2) = 36 Years

Sum of ages of A, B and C,

Now = (22 x 3) = 66 Years

Sum of ages of A and B,

Now = (36 +6)Years = 42 Years

THEREFORE, C’s age = (66 - 42)Years = 24 Years.

Sum of ages of A and B, 3 Years ago =(18 x 2) = 36 Years

Sum of ages of A, B and C,

Now = (22 x 3) = 66 Years

Sum of ages of A and B,

Now = (36 +6)Years = 42 Years

Therefore, C’s age = (66 - 42)Years = 24 Years.